list(map(len, ['4', 'fdd']))[1, 3]
Самая важная схема занятия:

list(map(len, ['4', 'fdd']))[1, 3]
1 in [1, 2, 3]True
1 in {1, 2, 3} # setsTrue
1 in (1, 2, 3) # tuplesTrue
d = {1: 'foo', 2: 'bar', 3: 'qux'}1 in dTrue
s = 'foobar''b' in sTrue
for item in [1, 3, 4]:
print(item)1
3
4
lst = [1, 2, 3]
x = iter(lst)
print(type(x))
print(x)<class 'list_iterator'>
<list_iterator object at 0x000001C1262DAC50>
next(x)1
next(x)2
next(x)3
next(x)--------------------------------------------------------------------------- StopIteration Traceback (most recent call last) Cell In[28], line 1 ----> 1 next(x) StopIteration:
from itertools import count
counter = count(start=13)next(counter)13
def repeater(value):
while True:
yield valuegenerator_obj = repeater('Эй')
next(generator_obj)'Эй'
next(generator_obj)'Эй'
numbers = [1, 2, 3, 4, 5, 6]
[x * x for x in numbers][1, 4, 9, 16, 25, 36]
lazy_squares = (x * x for x in numbers)lazy_squares<generator object <genexpr> at 0x7f671ce74cd0>
next(lazy_squares)1
gen = (x * x for x in range(2328346283764826348726347628374628376482763482763482634876))
print(next(gen))
print(next(gen))
print(next(gen))
# отложенные вычисления, т.е. один элемент по запросу0
1
4